## Algebra 2 (1st Edition)

$\theta=\dfrac{\pi}{6}$ or, $30^{\circ}$
We know that the trigonometric function $\sin^{-1} (1)$ has domain $[-1,1]$ and the range is: $[-\dfrac{\pi}{2}, \dfrac{\pi}{2}]$. So, $\theta = \sin^{-1} (\dfrac{1}{2})$ This implies that: $\theta=\dfrac{\pi}{6}$ or, $30^{\circ}$