Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Chapter Test - Page 843: 23

Answer

$\frac{187}{999}$

Work Step by Step

$0.187...=187(0.001)+187(0.001)^2+...=\frac{a_1}{1-r}=\frac{187(0.001)}{1-0.001}=\frac{0.187}{0.999}=\frac{187}{999}$
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