Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Chapter Test - Page 843: 14



Work Step by Step

We know that $\sum_{i=1}^n(n^2)=\frac{n(n+1)(2n+1)}{6}$ Hence $\sum_{i=1}^{28}(i^2)=\frac{28(28+1)(2(28)+1)}{6}=7714$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.