Answer
$130$
Work Step by Step
We know that $\sum_{i=1}^n(i)=\frac{n(n+1)}{2}$
Hence $\sum_{i=1}^{10}(4i-9)=10(-9)+4\sum_{i=1}^{10}(i)=-90+4\frac{10(10+1)}{2}=130$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - Chapter Test - Page 843: 15
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