## Algebra 2 (1st Edition)

$a_{1}=3$ $a_{2}=4$ $a_{3}=5$ $a_{4}=6$ $a_{5}=7$ $a_{6}=8$
Using basic addition, we find: $a_{1}=1+2$ $a_{2}=2+2$ $a_{3}=3+2$ $a_{4}=4+2$ $a_{5}=5+2$ $a_{6}=6+2$