Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.1 Define and Use Sequences and Series - 12.1 Exercises - Skill Practice - Page 798: 13


$\displaystyle \frac{2}{3},\ 1,\ \displaystyle \frac{6}{5}$, $\displaystyle \frac{4}{3}$, $\displaystyle \frac{10}{7}$, $\displaystyle \frac{3}{2}$

Work Step by Step

$a_{1}=\displaystyle \frac{2(1)}{1+2}=\frac{2}{3}$ $a_{2}=\displaystyle \frac{2(2)}{2+2}=\frac{4}{4}=1$ $a_{3}=\displaystyle \frac{2(3)}{3+2}=\frac{6}{5}$ $a_{4}=\displaystyle \frac{2(4)}{4+2}=\frac{8}{6}=\frac{4}{3}$ $a_{5}=\displaystyle \frac{2(5)}{5+2}=\frac{10}{7}$ $a_{6}=\displaystyle \frac{2(6)}{6+2}=\frac{12}{8}=\frac{3}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.