## Algebra 2 (1st Edition)

n-th term:$\quad a_{n}=\displaystyle \frac{2}{3n}$ The next term is $\displaystyle \quad a_{5}=\frac{2}{15}$
The n-th numerator is always 2. The nth denominator is a multiple of 3, starting with $3(1).$ So, the nth term is $a_{n}=\displaystyle \frac{2}{3n}$, and the next term is $a_{5}=\displaystyle \frac{2}{3\cdot 5}=\frac{2}{15}$