#### Answer

n-th term:$\quad a_{n}=\displaystyle \frac{2}{3n}$
The next term is $\displaystyle \quad a_{5}=\frac{2}{15}$

#### Work Step by Step

The n-th numerator is always 2.
The nth denominator is a multiple of 3, starting with $3(1).$
So, the nth term is $a_{n}=\displaystyle \frac{2}{3n}$,
and the next term is $a_{5}=\displaystyle \frac{2}{3\cdot 5}=\frac{2}{15}$