## Algebra 2 (1st Edition)

n-th term:$\quad a_{n}=n^{3}+1$ The next term is $\quad a_{5}=126$
Each term of the given sequence is close to the corresponding terms of $1,\ 8$, $27$, $64$, $...\qquad$ (cubes of natural numbers) The given sequence is interpreted as $1^{3}+1$, $2^{3}+1$, $3^{3}+1$, $4^{3}+1$, $...,\ n^{3}+1$,... We expect the next term to be $5^{3}+1=126$