## Algebra 2 (1st Edition)

Published by McDougal Littell

# Chapter 10 Counting Methods and Probability - Chapter Test - Page 737: 27

#### Answer

$6435$

#### Work Step by Step

We know that if we want to select $r$ objects out of $n$ disregarding the order, we can do this in $_nC_r=\frac{n!}{(n-r)!r!}$ ways. Thus the number of possibilities is: $_{15}C_8=\frac{15!}{(15-8)!8!}=6435$

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