Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - Chapter Test - Page 737: 8

Answer

$$126$$

Work Step by Step

We know the equation for combinations: $$nC_r = \frac{n!}{r!\left(n-r\right)!}$$ Thus, we find: $$\frac{9!}{5!\left(9-5\right)!}=126$$
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