Answer
$$c^{18}-12c^{15}d^2+60c^{12}d^4-160c^9d^6+240c^6d^8-192c^3d^{10}+64d^{12}$$
Work Step by Step
Using the binomial theorem to expand the binomial without multiplying the whole thing out, we find:
$$c^{18}-12c^{15}d^2+60c^{12}d^4-160c^9d^6+240c^6d^8-192c^3d^{10}+64d^{12}$$
