Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - Chapter Test - Page 737: 18

Answer

$65\%$

Work Step by Step

We know that $P(\text{A or B})=P(A)+P(B)-P(\text{A and B})$. Hence here: $P(B)=P(\text{A or B})+P(\text{A and B})-P(A)=80\%+20\%-35\%=65\%$
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