Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Skills Handbook - Simplifying Fractions - Exercises - Page 789: 7

Answer

9

Work Step by Step

We can solve these problems by comparing the numerator and the denominator. The denominator in the second fraction is 3 times greater than the denominator in the first fraction, so we know that the numerator of the second fraction must be 3 times greater as well. Thus, we multiply 3 times 3 to find that the missing number is 9.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.