Answer
$(2.61,12.61)$ and $(-4.61, 5.39)$
Work Step by Step
$y=x^2+2x-2$ and $y=x+10$
$x^2+2x-2=x+10$
$x^2+2x-12=0$
$x=(-b±\sqrt {b^2-4ac})/2a$
$x=(-2±\sqrt {2^2-4*1*-12})/2*1$
$x=(-2±\sqrt {4+48})/2*1$
$x=(-2±\sqrt {52})/2$
$x=(-2±2\sqrt {13})/2$
$x=(-1±\sqrt {13})$
$x=-1+\sqrt {13}$
$x=-1+3.6055$
$x=2.61$
$x=-1-\sqrt {13}$
$x=-1-3.6055$
$x=-4.61$
$y=x+10$
$y=2.61+10$
$y=12.61$
$y=x+10$
$y=-4.61+10$
$y=5.39$
