Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - Chapter Test - Page 593: 2

Answer

Please see the graph.
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Work Step by Step

Three points on the curve: $y=-x^2-2$ Line of symmetry: $x=-b/2a$ $x=-0/2*-1$ $x=0$ $y=-x^2-2$ $y=-0^2-2$ $y=0-2$ $y=-2$ $(0,-2)$ Let $x=1$: $y=-x^2-2$ $y=-1^2-2$ $y=-1-2$ $y=-3$ $(1,-3)$ Since $(1,-3)$ is one unit from the axis of symmetry, we also know $(-1,-3)$ is also one unit from the axis of symmetry and on the curve.
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