## Algebra 1

Three points on the curve: $y=-x^2-2$ Line of symmetry: $x=-b/2a$ $x=-0/2*-1$ $x=0$ $y=-x^2-2$ $y=-0^2-2$ $y=0-2$ $y=-2$ $(0,-2)$ Let $x=1$: $y=-x^2-2$ $y=-1^2-2$ $y=-1-2$ $y=-3$ $(1,-3)$ Since $(1,-3)$ is one unit from the axis of symmetry, we also know $(-1,-3)$ is also one unit from the axis of symmetry and on the curve.