## Algebra 1

Three points on the curve: $y=3x^2-7$ Line of symmetry: $x=-b/2a$ $x=-1*0/2*3$ $x=0/6 = 0$ $y=3x^2-7$ $y=3*(0^2)-7$ $y=3*0-7$ $y=-7$ $(0,-7)$ Let $x=3$: $y=3x^2-7$ $y=3*3^2-7$ $y=3*9-7$ $y=27-7$ $y=20$ $(3,20)$ Since $(3,20)$ is three units from the axis of symmetry, we also know that $(-3,20)$ is also three units from the axis of symmetry and on the line.