Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - Chapter Test - Page 593: 17


$x=1, -2.33$

Work Step by Step

$12x^2+16x-28=0$ $4(3x^2+4x-7=0)$ $3x^2+4x-7=0$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-4±\sqrt {4^2-4*3*-7})/2*3$ $x=(-4±\sqrt {16+84})/6$ $x=(-4±\sqrt {100})/6$ $x=(-4+10)/6$ and $x=(-4-10)/6$ $x=(-4+10)/6$ $x=6/6$ $x=1$ $x=(-4-10)/6$ $x=(-14)/6$ $x=-7/3 = -2.3$
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