## Algebra 1

a) Please see the graph. b) 16 feet c) No, the ball traveled 48 more feet between $t=1$ and $t=2$ than $t=0$ and $t=1$
a) The graph was made using graphing software. b) $h=-16t^2+72$ $h=-16(1)^2+72$ $h=-16*1+72$ $h=-16+72$ $h=56$ $72-56 = 16$ c) $h=-16t^2+72$ $h=-16(2)^2+72$ $h=-16*4+72$ $h=-64+72$ $h=8$ $72-8=64$ $64-16=48$