Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-1 Quadratic Graphs and Their Properties - Practice and Problem-Solving Exercises: 34

Answer

Option B

Work Step by Step

This quadratic's equation is f(x)=$ax^{2}+c$. Given the equation f(x)=$x^{2}-1$. The a value is 1 and since it is positive, the graph opens upwards(U) Therefore, it has a minimum. We calculate the minimum. Since there is no horizontal translation the minimum y-value is at f(0) f(0)= $(0)^{2}$ -1 f(0) = -1 The vertex is (0, -1)
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