Answer
Vertex: (0,5)
Axis of symmetry: x=0
Work Step by Step
Given the function
$y= -1.5x^{2} + 5$
We need to find the vertex and axis of symmetry
The basic form of the equation is
$y=a(k(x-d))^{2} + c$
Vertex:
The vertex for the base function $y= x^{2}$ is (0,0).
Since the d value is zero, the graph does not shift left or right thus the x value of the vertex is 0.
Since the c value is 5, the graph moves 5 units up thus the y value of the vertex is 5.
Therefore the vertex is (0,5)
Axis of symmetry:
The Axis of symmetry of a $y= x^{2}$ graph is x=0. Since the d value is zero, the graph does not shift left or right thus the axis of symmetry is still x=0.
