Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - Mid-Chapter Quiz: 20

Answer

$9d^{2}$+60d+100

Work Step by Step

In order to simplify the product $(3d+10)^{2}$ we must apply the rule that states that $(a+b)^{2}$=$a^{2}$+2ab+$b^{2}$, and we'll set a=3d and b=10. Therefore, $(3d+10)^{2}$=$(3d)^{2}$+2(3d)(10)+$10^{2}$ =$9d^{2}$+60d+100
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