## Algebra 1

$9d^{2}$+60d+100
In order to simplify the product $(3d+10)^{2}$ we must apply the rule that states that $(a+b)^{2}$=$a^{2}$+2ab+$b^{2}$, and we'll set a=3d and b=10. Therefore, $(3d+10)^{2}$=$(3d)^{2}$+2(3d)(10)+$10^{2}$ =$9d^{2}$+60d+100