## Algebra 1

16$b^{4}$+8$b^{2}$+20b=4b(4$b^{3}$+2b+5)
In order to factor 16$b^{4}$+8$b^{2}$+20b we must look for the greatest factor that can factor out of all three terms. This is known as the GCF (Greatest common factor). In this case, the GCF is 4b, because 4b is the greatest factor that can factor out of all three terms. After we factor out the 4b, in parentheses we will leave what multiplies to the corresponding term originally. For example, for the first term, after we factor out the 4b, we'll leave 4$b^{3}$ in the parentheses because 4b multiplied by 4$b^{3}$ is equal to 16$b^{4}$. Therefore, 16$b^{4}$+8$b^{2}$+20b=4b(4$b^{3}$+2b+5)