## Algebra 1

$2r^{2}-5r-12$
The area of a rectangle is: $A=L \times W$ Given that L = 2r+3 and W= r-4 We substitute it into the equation for area A = (2r+3)(r-4) We distribute the first bracket and multiply it with the second bracket. A= 2r(r-4)+3(r-4) To simplify the polynomial we apply the distributive property that states: a(b+c)=ab+ac A= $(2r \times r)+(2r \times -4)+(3 \times r) + (3 \times -4)$ A= $2r^{2}-8r+3r-12$ A= $2r^{2}-5r-12$ We add like terms to get final answer