Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - Chapter Review - 8-8 Factoring by Grouping: 78

Answer

$3(3a - 4)(a^{2}+ 2)$

Work Step by Step

$9a^{3} - 12a^{2} + 18a - 24$ We see that the terms have a common factor of 3 so we factor out a 3. $3(3a^{3} - 4a^{2} + 6a - 8)$ Factor by grouping, group the first two terms and last two terms together. $3(3a^{3} - 4a^{2}) + (6a - 8)$ Factor out the common factors from both parenthesis. $3(a^{2}(3a - 4) + 2(3a - 4)$ We take $(3a - 4)$ and factor it out which gives us. $3(3a - 4)(a^{2}+ 2)$
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