Algebra 1

Published by Prentice Hall

Chapter 8 - Polynomials and Factoring - Chapter Review - 8-8 Factoring by Grouping - Page 526: 75

Answer

$2d(d^{2} -1) (3d + 2)$

Work Step by Step

$6d^{4} + 4d^{3} - 6d^{2} - 4d$ We see the terms have a common factor of 2d so we factor the 2d out. $2d(3d^{3} + 2d^{2} - 3d - 2$) Factor by grouping, group the first two terms and last two terms together. $2d(3d^{3} + 2d^{2}) (- 3d - 2)$ Factor out the common factors from both parenthesis. $2d(d^{2} (3d + 2) -1(3d + 2))$ We take $(3d + 2)$ and factor it out which gives us. $2d(d^{2} -1) (3d + 2)$

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