Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - Chapter Review - 8-8 Factoring by Grouping - Page 526: 77


$(9z+4)(5z^{2} + 1)$

Work Step by Step

$45z^{3} + 20z^{2} + 9z + 4$ Factor by grouping, group the first two terms and last two terms together. $(45z^{3} + 20z^{2}) + (9z + 4)$ Factor out the common factors from both parenthesis. $5z^{2}(9z+4) + 1(9z+4)$ We take $(9z+4)$ and factor it out which gives us. $(9z+4)(5z^{2} + 1)$
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