Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - Chapter Review - 8-8 Factoring by Grouping - Page 526: 77

Answer

$(9z+4)(5z^{2} + 1)$

Work Step by Step

$45z^{3} + 20z^{2} + 9z + 4$ Factor by grouping, group the first two terms and last two terms together. $(45z^{3} + 20z^{2}) + (9z + 4)$ Factor out the common factors from both parenthesis. $5z^{2}(9z+4) + 1(9z+4)$ We take $(9z+4)$ and factor it out which gives us. $(9z+4)(5z^{2} + 1)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.