#### Answer

$(11b - 6)(b^{2} + 1)$

#### Work Step by Step

$11b^{3} - 6b^{2} + 11b - 6$
Factor by grouping, group the first two terms and last two terms together.
$(11b^{3} - 6b^{2}) + (11b - 6)$
Factor out the common factors from both parenthesis.
$b^{2}(11b - 6) + 1(11b - 6)$
We take $(11b - 6)$ and factor it out which gives us.
$(11b - 6)(b^{2} + 1)$