Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises: 13

Answer

$(2g-3)(4g-1)$

Work Step by Step

Rewrite -14g as -2g -12g $8g^{2} + -14g + 3 = 8g^{2} - 2g - 12g +3$ Factor out GCF of each pair of terms, which would be $2g(4g-1)-3(4g-1)$ Now use distributive property = $(2g-3)(4g-1)$
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