Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises: 11

Answer

$(4p+3)(p+1)$

Work Step by Step

Rewrite 7p as 4p + 3p $4p^{2} + 7p + 3 = 4p^{2} + 4p + 3p +3$ Factor out GCF of each pair of terms, which would be $4p(p+1) + 3(p+1)$ Now use distributive property = $(4p+3)(p+1)$
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