Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises: 10

Answer

$(2n-3)(2n-1)$

Work Step by Step

Rewrite -8n as -2n + -6n $4n^{2} - 8n + 3 = 4n^{2} -2n - 6n +3$ Factor out GCF of each pair of terms, which would be $2n(2n-1) + -3(2n-1)$ Now use distributive property = $(2n-3)(2n-1)$
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