Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 508: 12

Answer

$(2r-5)(3r-4)$

Work Step by Step

Rewrite -23r as -8r + -15r $6r^{2} - 23r + 20 = 6r^{2} - 8r - 15r + 20$ Factor out GCF of each pair of terms, which would be $2r(3r-4) -5(3r-4)$ Now use distributive property = $(2r-5)(3r-4)$
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