Answer
$\frac{27t^6}{8}$
Work Step by Step
$(3t^2)^{3}*(2t^0)^{-3}$
$3^3*(t^2)^3*2^{-3}*1^{-3}$
$27*t^2*t^2*t^2*1/(2^3)*1$
$27/8*t^6$
$\frac{27t^6}{8}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - Mid-Chapter Quiz - Page 439: 8
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