Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - Mid-Chapter Quiz: 3

Answer

$6x^{17}$

Work Step by Step

We start with the given expression: $(2x^5)(3x^{12})$ We re-arrange and regroup the factors using the associative and commutative properties of multiplication: $(2\times3)(x^5\times x^{12})$ We multiply the constants: $6(x^5\times x^{12})$ To multiply powers with the same base, we add the exponents: $ 6x^{5+12}=6x^{17}$
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