Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - Mid-Chapter Quiz - Page 439: 20



Work Step by Step

We start with the given expression: $(9\times10^{-3})^2$ To raise a product to a power, we raise each factor to the power and multiply: $9^2(10^{-3})^2$ We simplify the constant power: $81(10^{-3})^2$ To raise a power to a power, we multiply the exponents: $81(10^{-3\times2})=81\times10^{-6}$ We rewrite in scientific notation: $8.1\times10^{-5}$
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