## Algebra 1

Equation y = $0.1^{x}$ f(-2) = 100 f(-1) = 10 f(0) = 1 f(1) = 0.1 f(2) = 0.01 As the values of domain increase, the values of the range decrease
Equation y = $0.1^{x}$ f(-2) = $0.1^{-2}$ = $\frac{1}{0.1^{2}}$ = $\frac{1}{0.01}$ = 100 f(-1) = $0.1^{-1}$ = $\frac{1}{0.1^{1}}$ = $\frac{1}{0.1}$ = 10 f(0) = $0.1^{0}$ = 1 (Anything to the power of 0 is 1) f(1) = $0.1^{1}$ = 0.1 f(2) = $0.1^{2}$ = 0.01 $\times$ 0.1 = 0.01 As the values of domain (the x-values) increase, the values of the range (y-values) decrease. As they go from 100 to 10 to 1 to 0.1 and then to 0.01.