Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-6 Exponential Functions - Practice and Problem-Solving Exercises: 32

Answer

$f(-2) = 100$ $f(-1) =10$ $f(0) = 1$ $f(1) = 0.1$ $f(2) = 0.01$ $f(3) = 0.001$ The values of the range increase as the values of the domain decrease.

Work Step by Step

We know that $a^{-n} = \frac{1}{a^n}$ $f(-2) = 0.1^{-2} = \frac{1}{0.1^2} = \frac{1}{0.01} = 100$ $f(-1) = 0.1^{-1} = \frac{1}{0.1}=10$ $f(0) = 0.1^0 = 1$ $f(1) = 0.1^1 = 0.1$ $f(2) = 0.1^2 = 0.01$ $f(3) = 0.1^3 = 0.001$ The values of the range increase as the values of the domain decrease.
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