## Algebra 1

$f(-2) = 100$ $f(-1) =10$ $f(0) = 1$ $f(1) = 0.1$ $f(2) = 0.01$ $f(3) = 0.001$ The values of the range increase as the values of the domain decrease.
We know that $a^{-n} = \frac{1}{a^n}$ $f(-2) = 0.1^{-2} = \frac{1}{0.1^2} = \frac{1}{0.01} = 100$ $f(-1) = 0.1^{-1} = \frac{1}{0.1}=10$ $f(0) = 0.1^0 = 1$ $f(1) = 0.1^1 = 0.1$ $f(2) = 0.1^2 = 0.01$ $f(3) = 0.1^3 = 0.001$ The values of the range increase as the values of the domain decrease.