## Algebra 1

Published by Prentice Hall

# Chapter 7 - Exponents and Exponential Functions - 7-6 Exponential Functions - Practice and Problem-Solving Exercises - Page 451: 33

#### Answer

Equation y = $2.5^{x}$ f(-2) = $\frac{1}{6.25}$ f(-1) = $\frac{1}{2.5}$ f(0) = 1 f(1) = 2.5 f(2) = 6.5 As the values of domain increase, the values of the range increase

#### Work Step by Step

Equation y = $2.5^{x}$ f(-2) = $2.5^{-2}$ = $\frac{1}{2.5^{2}}$ = $\frac{1}{6.25}$ f(-1) = $2.5^{-1}$ = $\frac{1}{2.5^{1}}$ = $\frac{1}{2.5}$ f(0) = $2.5^{0}$ = 1 f(1) = $2.5^{1}$ = 2.5 f(2) = $2.5^{2}$ = 6.5 As the values of domain increase, the values of the range increase

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