# Chapter 7 - Exponents and Exponential Functions - 7-6 Exponential Functions - Practice and Problem-Solving Exercises: 31

$f(-2) = \frac{4}{25}$ $f(-1)=\frac{2}{5}$ $f(0) = 1$ $f(1) = 2.5$ $f(2) = 6.25$ $f(3) = 15.625$ The values of the range increase as the values of the domain increase.

#### Work Step by Step

We know that $a^{-n} = \frac{1}{a^n}$ $f(-2) = 2.5^{-2} = \frac{1}{2.5^2} = \frac{1}{6.25} = \frac{4}{25}$ $f(-1) = 2.5^{-1} = \frac{1}{2.5}=\frac{2}{5}$ $f(0) = 2.5^0 = 1$ $f(1) = 2.5^1 = 2.5$ $f(2) = 2.5^2 = 6.25$ $f(3) = 2.5^3 = 15.625$ The values of the range increase as the values of the domain increase.

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