Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-6 Exponential Functions - Practice and Problem-Solving Exercises - Page 451: 31

Answer

$f(-2) = \frac{4}{25}$ $f(-1)=\frac{2}{5}$ $f(0) = 1$ $f(1) = 2.5$ $f(2) = 6.25$ $f(3) = 15.625$ The values of the range increase as the values of the domain increase.

Work Step by Step

We know that $a^{-n} = \frac{1}{a^n}$ $f(-2) = 2.5^{-2} = \frac{1}{2.5^2} = \frac{1}{6.25} = \frac{4}{25}$ $f(-1) = 2.5^{-1} = \frac{1}{2.5}=\frac{2}{5}$ $f(0) = 2.5^0 = 1$ $f(1) = 2.5^1 = 2.5$ $f(2) = 2.5^2 = 6.25$ $f(3) = 2.5^3 = 15.625$ The values of the range increase as the values of the domain increase.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.