Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 59



Work Step by Step

The given expression : $\frac{(2^{4})^{3}}{2^{15}}=$ $\frac{2^{12}}{2^{15}}$ , (since $(a^{m})^{n}=$ $a^{mn}$) This can be written as : $2^{12}$ X $2^{-15}$ (since $a^{-1}=$ $\frac{1}{a}$) Thus, this becomes : $2^{-3}=$ $\frac{1}{8}$
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