Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Practice and Problem-Solving Exercises: 46

Answer

$\frac{1}{8n^{3}}$

Work Step by Step

Given : $(\frac{2n^{2-1}}{1}$$)^{-3}=$ $(\frac{2n}{1}$$)^{-3}=$ $2^{-3}\times n^{-3}=$ $\frac{1}{8}\times$ $\frac{1}{n^{3}}=$ $\frac{1}{8n^{3}}$ (since $(ab)^{m}=$ $a^{m}b^{m}$ and $a^{-m}=$ $\frac{1}{a^{m}}$)
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