Answer
$b^{15}$
Work Step by Step
Given : $(\frac{b^{4-7}}{1}$$)^{-5}=$ $(b^{-3})^{-5}=$ $b^{-3\times-5}$ $=b^{15}$ , since $(a^{m})^{n}=$ $a^{mn}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 47
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