## Algebra 1

$4 \times 10^{-5}$
$\dfrac{a^m}{a^n}=a^{m-n}, a\ne0$ Divide the corresponding parts while using the rule above to find: $=\dfrac{3.6}{9} \times \dfrac{10^{-10}}{10^{-6}} \\=0.4 \times 10^{-10-(-6)} \\=0.4 \times 10^{-10+6} \\=0.4 \times 10^{-4} \\=(4 \cdot 10^{-1}) \times 10^{-4} \\=4 \times 10^{-1+(-4)} \\=4 \times 10^{-5}$