## Algebra 1

Multiply the first equation by 2. Add the equations. $5x-3y=10\ \ \ \ \$multiply by 2$\ \ \ \ 10x-6y=20$ $10x+6y=20\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \underline{10x+6y=20}$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 20x\ \ \ \ \ \ \ \ =40$ Solve for x. $20x=40$ $20x\div20=40\div20$ $x=2$ Substitute 2 for x in either equation to solve for y. $10x+6y=20$ $10(2)+6y=20$ $20+6y-20=20-20$ $6y=0$ $6y\div6=0\div6$ $y=0$