## Algebra 1

Multiply the second equation by 2, then add the equations to eliminate x. $6x+4y=42\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 6x+4y=\ \ \ 42$ $-3x+3y=-6\ \ \ \$multiply by -2$\ \ \ \ \ \ \underline{-6x+6y=-12}$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 10y=\ \ 30$ Solve for y. $10y=30$ $10y\div10=30\div10$ $y=3$ Substitute 3 for y in either equation and solve for x. $6x+4(3)=42$ $6x+12-12=42-12$ $6x=30$ $6x\div6=30\div6$ $x=5$