## Algebra 1

Multiply the first equation by 2, then add the equations to eliminate y. $3x+\ \ y=\ \ \ 5\ \ \ \$multiply by 2$\ \ \ \ 6x+2y=\ 10$ $2x-2y=-2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \underline{2x-2y=-2}$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 8x\ \ \ \ \ \ \ \ \ =\ \ \ 8$ Solve for x. $8x=8$ $8x\div8=8\div8$ $x=1$ Substitute 1 for x in either equation and solve for y. $3(1)+y=5$ $3+y-3=5-3$ $y=2$