## Algebra 1

Multiply the first equation by 8. Multiply the second equation by 9. Add the two equations to eliminate y. $5x-9y=-43\ \ \ \$multiply by 8$\ \ \ \ 40x-72y=-344$ $3x+8y=\ \ \ 68\ \ \ \$multiply by 9$\ \ \ \ \underline{27x+72y=\ \ \ 612}$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 67x\ \ \ \ \ \ \ \ \ \ \ =\ \ \ 268$ Solve for x. $67x=268$ $67x\div67=268\div67$ $x=4$ Substitute 4 for x in either equation and solve for y. $3(4)+8y=68$ $12+8y-12=68-12$ $8y=56$ $8y\div8=56\div8$ $y=7$