## Algebra 1

$y = -1/2* x + 5/2$
perpendicular to $y + 1 = 2*(x-3)$, passes through (5, 0) $y + 1 = 2*(x-3)$ $y + 1 = 2x -6$ $y + 1-1 = 2x -6-1$ $y = 2x -7$ perpendicular slopes: $2 * m = -1$ $2 * m * 1/2 = -1 * 1/2$ $m = -1/2$ $y = mx+b$ $y = -1/2* x + b$ $0 = -1/2* 5 + b$ $0 = -5/2 + b$ $0 + 5/2 = -5/2 + b + 5/2$ $5/2 = b$ $y = -1/2* x + 5/2$