Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 5 - Linear Functions - 5-6 Parallel and Perpendicular Lines - Practice and Problem-Solving Exercises - Page 331: 20



Work Step by Step

Given: y=$\frac{1}{2}$x-1 ,(-2,3) Since its perpendicular, the slope will be the reciprocal of the other equation's slope ($\frac{1}{2}$) which is -2.So y=-2x+b Using the points given, plug into the equation: y=-2x+b 3=-2(-2)+b 3=4+b b=-1 So the equation would be y=-2x-1
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