Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 2 - Solving Equations - 2-7 Solving Proportions - Practice and Problem-Solving Exercises - Page 127: 35


$$n = 4\frac{2}{3}$$ Used the Cross Products Property for the first step.

Work Step by Step

Since there aren't any equations in either of the numericators or denominators it would be easier to solve using the Cross Products Property first to get the variable on one side and the numbers without variables on the other sides. Doing that will give you $9n = 42$. Now all you have to do is divide both sides by 9 which will give you $n = 4\frac{2}{3}$
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