## Algebra 1

$b=-6\frac{2}{3}$
$\frac{3}{3b+4}=\frac{2}{b-4}$ cross multiply $2(3b+4)=3(b-4)$ distributive property $6b+8=3b-12$ subtract 3b from both sides; subtract 8 from both sides $6b+8-3b-8=3b-12-3b-8$ combine like terms $3b=-20$ divide both sides by 3 $3b\div3=-20\div3$ simplify $b=-6\frac{2}{3}$